std::filesystem::path::root_directory
From cppreference.com
                    
                                        
                    < cpp | filesystem | path
                    
                                                            
                    |   path root_directory() const;  | 
(since C++17) | |
Returns the root directory of the generic-format path. If the path (in generic format) does not include root directory, returns path().
Parameters
(none)
Return value
The root directory of the path.
Exceptions
May throw implementation-defined exceptions.
Example
Run this code
#include <filesystem> #include <iostream> namespace fs = std::filesystem; int main() { fs::path p = fs::current_path(); std::cout << "The current path " << p << " decomposes into:\n" << "root name " << p.root_name() << '\n' << "root directory " << p.root_directory() << '\n' << "relative path " << p.relative_path() << '\n'; }
Possible output:
The current path "C:\Users\abcdef\Local Settings\temp" decomposes into: root name "C:" root directory "\" relative path "Users\abcdef\Local Settings\temp"
See also
|   returns the root-name of the path, if present  (public member function)  | |
|   returns the root path of the path, if present  (public member function)  |