std::move_iterator<Iter>::operator*,->
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                    < cpp | iterator | move iterator
                    
                                                            
                    reference operator*() const;  | 
(1) | (since C++11)  (constexpr since C++17)  | 
pointer operator->() const;  | 
(2) | (since C++11)  (constexpr since C++17) (deprecated in C++20)  | 
Returns an rvalue reference or pointer to the current element.
Return value
2) 
currentNotes
operator-> is deprecated because deferencing its result may yield an lvalue. This may lead to unintended behavior.
Example
Run this code
#include <iomanip> #include <iostream> #include <iterator> #include <string> #include <vector> void print(auto rem, const auto& v) { for (std::cout << rem; const auto& e : v) std::cout << std::quoted(e) << ' '; std::cout << '\n'; } int main() { std::vector<std::string> p{"alpha", "beta", "gamma", "delta"}, q; print("1) p: ", p); for (std::move_iterator it{p.begin()}, end{p.end()}; it != end; ++it) { it->push_back('!'); // calls -> string::push_back(char) q.emplace_back(*it); // *it <- overload (1) } print("2) p: ", p); print("3) q: ", q); std::vector v{1, 2, 3}; std::move_iterator it{v.begin()}; // *it = 13; // error: using rvalue as lvalue }
Possible output:
1) p: "alpha" "beta" "gamma" "delta" 2) p: "" "" "" "" 3) q: "alpha!" "beta!" "gamma!" "delta!"
Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
| DR | Applied to | Behavior as published | Correct behavior | 
|---|---|---|---|
| LWG 2106 | C++11 | operator* would return a dangling reference if * current yields a prvalue
 | 
returns the object in this case  | 
See also
|    (C++11)  | 
  accesses an element by index  (public member function)  |