operator==,!=,<,<=,>,>=,<=>(std::reverse_iterator)
From cppreference.com
                    
                                        
                    < cpp | iterator | reverse iterator
                    
                                                            
                    |   Defined in header  <iterator>
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template< class Iter1, class Iter2 > bool operator==( const std::reverse_iterator<Iter1>& lhs,  | 
(1) | (constexpr since C++17) | 
template< class Iter1, class Iter2 > bool operator!=( const std::reverse_iterator<Iter1>& lhs,  | 
(2) | (constexpr since C++17) | 
template< class Iter1, class Iter2 > bool operator< ( const std::reverse_iterator<Iter1>& lhs,  | 
(3) | (constexpr since C++17) | 
template< class Iter1, class Iter2 > bool operator<=( const std::reverse_iterator<Iter1>& lhs,  | 
(4) | (constexpr since C++17) | 
template< class Iter1, class Iter2 > bool operator> ( const std::reverse_iterator<Iter1>& lhs,  | 
(5) | (constexpr since C++17) | 
template< class Iter1, class Iter2 > bool operator>=( const std::reverse_iterator<Iter1>& lhs,  | 
(6) | (constexpr since C++17) | 
|   template< class Iter1, std::three_way_comparable_with<Iter1> Iter2 > constexpr std::compare_three_way_result_t<Iter1, Iter2>  | 
(7) | (since C++20) | 
Compares the underlying iterators of lhs and rhs.
- The result of equality comparisons are preserved (i.e. equal underlying iterators imply equal reverse iterators).
 - The result of relational comparisons are reversed (i.e. a greater underlying iterator implies a lesser reverse iterator).
 
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 1) This overload participates in overload resolution only if lhs.base() == rhs.base() is well-formed and convertible to bool. 
2) This overload participates in overload resolution only if lhs.base() != rhs.base() is well-formed and convertible to bool. 
3) This overload participates in overload resolution only if lhs.base() > rhs.base() is well-formed and convertible to bool. 
4) This overload participates in overload resolution only if lhs.base() >= rhs.base() is well-formed and convertible to bool. 
5) This overload participates in overload resolution only if lhs.base() < rhs.base() is well-formed and convertible to bool. 
6) This overload participates in overload resolution only if lhs.base() <= rhs.base() is well-formed and convertible to bool. 
 | 
(since C++20) | 
Parameters
| lhs, rhs | - | iterator adaptors to compare | 
Return value
1) lhs.base() == rhs.base()
2) lhs.base() != rhs.base()
3) lhs.base() > rhs.base()
4) lhs.base() >= rhs.base()
5) lhs.base() < rhs.base()
6) lhs.base() <= rhs.base()
7) rhs.base() <=> lhs.base()
Notes
operator<=> returns rhs.base() <=> lhs.base() rather than lhs.base() <=> rhs.base() because this is a reverse iterator.
Example
Run this code
#include <cassert> #include <iterator> int main() { int a[]{0, 1, 2, 3}; // ↑ └───── x, y // └──────── z // “x” and “y” are equal, but “x” is less than “z” (reversely) std::reverse_iterator<int*> x{std::rend(a) - std::size(a)}, y{std::rend(a) - std::size(a)}, z{std::rbegin(a) + 1}; // two-way comparisons assert( x == y ); assert(!(x != y)); assert(!(x < y)); assert( x <= y ); assert(!(x == z)); assert( x != z ); assert( x < z ); assert( x <= z ); // three-way comparisons assert( x <=> y == 0 ); assert(!(x <=> y < 0)); assert(!(x <=> y > 0)); assert(!(x <=> z == 0)); assert( x <=> z < 0 ); assert(!(x <=> z > 0)); }
Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
| DR | Applied to | Behavior as published | Correct behavior | 
|---|---|---|---|
| LWG 280 | C++98 | heterogeneous assignment was not allowed | allowed |