std::reverse_iterator<Iter>::operator*,->
From cppreference.com
                    
                                        
                    < cpp | iterator | reverse iterator
                    
                                                            
                    reference operator*() const;  | 
(1) | (constexpr since C++17) | 
| (2) | ||
pointer operator->() const;  | 
(constexpr since C++17)  (until C++20)  | 
|
|   constexpr pointer operator->() const     requires (std::is_pointer_v<Iter> ||  | 
(since C++20) | |
Returns a reference or pointer to the element previous to current.
| Member function | Equivalent to | ||||||
|---|---|---|---|---|---|---|---|
| operator* | Iter tmp = current; return *--tmp;
 | ||||||
| operator-> | 
  | 
Return value
As described above.
Example
Run this code
#include <complex> #include <iostream> #include <iterator> #include <vector> int main() { using RI0 = std::reverse_iterator<int*>; int a[]{0, 1, 2, 3}; RI0 r0{std::rbegin(a)}; std::cout << "*r0 = " << *r0 << '\n'; *r0 = 42; std::cout << "a[3] = " << a[3] << '\n'; using RI1 = std::reverse_iterator<std::vector<int>::iterator>; std::vector<int> vi{0, 1, 2, 3}; RI1 r1{vi.rend() - 2}; std::cout << "*r1 = " << *r1 << '\n'; using RI2 = std::reverse_iterator<std::vector<std::complex<double>>::iterator>; std::vector<std::complex<double>> vc{{1, 2}, {3, 4}, {5, 6}, {7, 8}}; RI2 r2{vc.rbegin() + 1}; std::cout << "vc[2] = (" << r2->real() << ',' << r2->imag() << ")\n"; }
Output:
*r0 = 3 a[3] = 42 *r1 = 1 vc[2] = (5,6)
Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
| DR | Applied to | Behavior as published | Correct behavior | 
|---|---|---|---|
| LWG 2188 | C++11 | operator-> used & to take address
 | 
uses std::addressof instead | 
See also
|   accesses an element by index  (public member function)  |